Divisor 14503

Prime Number:
Yes!
Divisibility test:
The "Steve Griffiths Test"
Test Discovered by:
Matt Parker
Date:
11/11/2024

The "Steve Griffiths Test" for Divisibility by 14503

To determine if any number is divisible by 14503, apply the "Steve Griffiths Test":

  1. If your number ("X") has 7 digits or more, separate the last (smallest) 6 digits from the rest. This makes two smaller numbers, call them Left and Right (note: don't add in trailing zeros to L). If there are fewer than 7 digits, L = 0 and therefore R = X.
  2. Multiply L by 707 and subtract this from R.
  3. Take that result and cross off its final digit (units). Take this new number and add 4351 times the digit you just crossed off. Call this final result "Y".
  4. Y will be much smaller than X, but we have preserved divisibility by 14503. That is, your original number is divisible by 14503 if (and only if) Y is. Now that it's much smaller, with basic knowledge of your 14503-times tables, it should be easy to visually see if Y is divisible by 14503. If the Y is still much larger than 14503, the above process can be repeated until it does reduce to within small multiples of 14503.

Easy!