Divisor 20107
- Prime Number:
- Yes!
- Divisibility test:
- The "Patrick Fitzgerald Test"
- Test Discovered by:
- Matt Parker
- Date:
- 11/11/2024
The "Patrick Fitzgerald Test" for Divisibility by 20107
To determine if any number is divisible by 20107, apply the "Patrick Fitzgerald Test":
- If your number ("X") has 6 digits or more, separate the last (smallest) 5 digits from the rest. This makes two smaller numbers, call them Left and Right (note: don't add in trailing zeros to L). If there are fewer than 6 digits, L = 0 and therefore R = X.
- Multiply L by 535 and subtract this from R.
- Take that result and cross off its final digit (units). Take this new number and subtract 6032 times the digit you just crossed off. Call this final result "Y".
- Y will be much smaller than X, but we have preserved divisibility by 20107. That is, your original number is divisible by 20107 if (and only if) Y is. Now that it's much smaller, with basic knowledge of your 20107-times tables, it should be easy to visually see if Y is divisible by 20107. If the Y is still much larger than 20107, the above process can be repeated until it does reduce to within small multiples of 20107.
Easy!