Divisor 8179

To determine if any number is divisible by 8179, apply the "Emily!! Test":

1. If your number ("X") has 5 digits or more, separate the last (smallest) 4 digits from the rest. This makes two smaller numbers, call them L^eft and R^ight (note: don't add in trailing zeros to L). If there are fewer than 5 digits, L = 0 and therefore R = X.
2. Multiply L by 1821 and add to R.
3. Take that result and cross off its final digit (units). Take this new number and add 818 times the digit you just crossed off. Call this final result "Y".
4. Y will be much smaller than X, but we have preserved divisibility by 8179. That is, your original number is divisible by 8179 if (and only if) Y is. Now that it's much smaller, with basic knowledge of your 8179-times tables, it should be easy to visually see if Y is divisible by 8179. If the Y is still much larger than 8179, the above process can be repeated until it does reduce to within small multiples of 8179.

Easy!