Divisor 18503
- Prime Number:
- Yes!
- Divisibility test:
- The "Conor McCullough Test"
- Test Discovered by:
- Matt Parker
- Date:
- 11/11/2024
The "Conor McCullough Test" for Divisibility by 18503
To determine if any number is divisible by 18503, apply the "Conor McCullough Test":
- If your number ("X") has 7 digits or more, separate the last (smallest) 6 digits from the rest. This makes two smaller numbers, call them Left and Right (note: don't add in trailing zeros to L). If there are fewer than 7 digits, L = 0 and therefore R = X.
- Multiply L by 838 and add to R.
- Take that result and cross off its final digit (units). Take this new number and add 5551 times the digit you just crossed off. Call this final result "Y".
- Y will be much smaller than X, but we have preserved divisibility by 18503. That is, your original number is divisible by 18503 if (and only if) Y is. Now that it's much smaller, with basic knowledge of your 18503-times tables, it should be easy to visually see if Y is divisible by 18503. If the Y is still much larger than 18503, the above process can be repeated until it does reduce to within small multiples of 18503.
Easy!